1. The correct order of ONO bond angles in N2O5, N2O3 and N2O4 are respectively
Ans: N2O5 > N2O3 > N2O4
Sol:
In N2O5 (134°), In N2O3 (130°), In N2O4 (121°)
2. The colour of penta aqua nitrosonium iron (I) sulphate is
Ans: Brown
Sol: [Fe(H2O)5 NO]+2 is brown ring
3. p-p bond is formed in
Ans: H4P2O6
Sol:
4. Incorrect statement among the following is
1) N2O3 is blue coloured solid 2) N2O5 is yellow coloured solid
3) NO is colourless gas 4) NO2 is brown gas
Ans: 2 (N2O5 is yellow coloured solid)
Sol:
N2O5 is colourless solid
5. Now-a-days catalyst used in the synthesis of NH3 by Haber's process is
Ans: Al2O3 + K2O + Iron Oxide
Sol:
Al2O3 + K2O + Iron Oxide is catalyst
6. The halide of group 15 elements having lowest boiling point is
Ans: PH3
Sol:
B.P. for NH3 (240 K), PH3 (186 K), SbH3 (255 K), Bi H3 (290 K)
7. The signs of ∆G, ∆H and ΔS during decomposition of O3 are respectively
Ans: −Ve, −Ve, +Ve
Sol:
∆G = −ve, ∆H = −ve, ∆S = +ve
8. O2 gas is not liberated when O3 reacts with
Ans: C2H4
Sol:
C2H4 + O3→ C2H4 . O3
9. Rhombic Sulphur is readily soluble in
Ans: CS2
Sol:
Rhombic Sulphur is readily soluble in CS2
10. Gas/ Gases produced when carbon reacts with conc. H2SO4 is/ are
1) CO2 2) SO2 3) both CO2 & SO2 4) CO
Ans: 3 (both CO2 & SO2)
Sol:
C + 2 H2SO4 (Conc.) → CO2 + 2 SO2 + 2 H2O
11. A set of amphoteric oxides among the following is
1) SO2, Cl2O7, N2O5 2) ZnO, PbO, SnO2
3) Mn2O7, CrO3, V2O5 4) None of the above
Ans: 2 (ZnO, PbO, SnO2)
Sol:
ZnO, PbO, SnO2 are amphoteric
12. S−S bond is formed in
Ans: H2S2O4
Sol:
13. The oxide used in the estimation of CO is
Ans: I2O5
Sol:
I2O5 is used in the estimation of CO.
14. The compound used in removing Pu as PuF6 from spent nuclear fuel is
Ans: O2F2
Sol:
Pu + 3 O2F2→ PuF6 + 3 O2
15. Arsenic impurities are removed in Arsenic purifier in Contact process by
Ans: gelatinous hydrated Fe(OH)3
Sol:
Gelatinous hydrated Fe(OH)3 removes Arsenic impurities.
16. Compound(s) used in the enrichment of U235 to produce UF6 is/ are
1) ClF3 2) BrF3 3) both ClF3 & BrF3 4) IF7
Ans: 3 (both ClF3 & BrF3)
Sol:
ClF3 & BrF3 are used to produce UF6
U + 3ClF3→ UF6 + 3 ClF
U + 3 BrF3→ UF6 + 3 BrF
17. Which of the following orders is not in accordance with the property stated against it?
1) ClO− > ClO2− > ClO3− > ClO4 −: acidic nature
2) F2 > Cl2 > Br2 > I2 : Bond dissociation energy
3) F2 > Cl2 > Br2 > I2 : Oxidising power
4) HF > HI > HBr > HCl : Boiling Points
Ans: 2 (F2 > Cl2 > Br2 > I2 : Bond dissociation energy)
Sol:
Bond dissociation energy:
Cl2 (243) > Br2 (193) > F2 (159) > I2 (151 KJmol−1)
18. Which of the following reaction is not feasible?
1) 2 KI + Br2 → 2 KBr + I2 2) 2 KBr + Cl2→ 2 KCl + Br2
3) 2 H2O + 2 F2→ 4 HF + O2 4) 2 KBr + I2→ 2 KI + Br2
Ans: 4 (2 KBr + I2→ 2 KI + Br2)
Sol:
A halogen with less atomic number can only oxidise a halogen with more atomic number.
19. Cl2 is not evolved in the reaction
Ans: NaNO2 + HCl →
Sol:
2 NaNO2 + 2 HCl → 2 NaCl + NO + NO2 + H2O
20. SO2 acts as temporary bleaching agent but Cl2 acts as permanent bleaching agent. Why?
Ans: Cl2 bleaches due to oxidation but SO2 is due to reduction
Sol:
Cl2 + H2O → 2 HCl + (O)
SO2 + 2 H2O → H2SO4 + 2 (H)
21. S8 on reaction with Cl2 to form a compound X. X is isostructural with
1) H2O2 2) O2F2 3) both H2O2 & O2F2 4) XeF2
Ans: 3 ( both H2O2 & O2F2)
Sol:
S8 + 4 Cl2→ 4 S2Cl2 S2Cl2, H2O2, O2F2 all are having open book shape
22. When HCl reacts with finely powdered iron, it forms a coloured precipitate. The colour of the precipitate is
Ans: pale green
Sol:
Fe + 2 HCl 
FeCl2 + H2
(Pale green)
23. The decay products of radium are
Ans: one radioactive inert gas, one nonradioactive inert gas
Sol:
88Ra226→ 86Rn222 + 2He4
24. Neil Bartlett realised that I.E1 of Xe is identical with that of the gas
Ans: O2
Sol:
IE1 of O2 = 1175 KJ mol−1
I.E1 of Xe = 1170 KJ mol−1
25. Names of the compounds are formed when 5 times, 20 times of F2 reacts with Xe and excess of the Xe reacts with F2 are respectively
Ans: XeF4, XeF6, XeF2
Sol:
26. Number of lone pairs on Xe in XeO3, XeOF4, XeF6, XeF4 and XeF2 are respectively
Ans: 1, 1, 1, 2, 3
