Directions (Qs. 1 - 27): What will come in place of question mark (?) in the following questions?
1. What should come in place of ?
65847 + 25684 − 12563 = ?
A) 78968 B) 65432 C) 56432 D) 64123 E) 76421
Sol: 65847 + 25684 − 12563 = 78968
Ans: A
2. 3624 ÷ 14 ÷ 6 = ?
A) 51.65 B) 43.14 C) 23.21 D) 65.14 E) 45.62
3. 592 − 292 + 312 = ?
A) 1201 B) 3601 C) 2202 D) 3402 E) None of the above
Sol: 592 − 292 + 312 = ?
= (59 × 59) − (29 × 29) + (31 × 31)
= 3481 − (841) + (961)
= 3481 − 841 + 961 = 3601
Ans: B
4. (308.40 × ?) ÷ 220 + 37 = 44
A) 2 B) 8 C) 5 D) 12 E) 16
Sol: = ((308.40 × 5) ÷ 220) + 37
= (1542 ÷ 220) + 37 =
(7.0) + 37 = 44
Ans: C
5. (29 × 62 − 130) ÷ 25 = ?
A) 31.22 B) 54.32 C) 66.72 D) 78.12 E) 32.56
Sol: (29 × 62 − 130) ÷ 25
6. 15.25 × 6.2 + 84.33 = ?
A) 112.32 B) 114 C) 115.67 D) 119 E) 178.88
Sol: (15.25 × 6.2) + 84.33 = 178.88
Ans: E
9. 50% of 280 × 35% of 1200 = ?
A) 43200 B) 32400 C) 64000 D) 58800 E) None of the above
Sol: = 50% of 280 × 35% of 1200
10. 40% of 280 + 60% of 1880 = 85 % of 1400 + ?
A) 25 B) 50 C) 80 D) 45 E) 70
Sol: = 40% of 280 + 60% of 1880 = 85 % of 1400 + ?
11. 1980 ÷ 72 + 125 = ? − 692
A) 2334.2 B) 4467.7 C) 3345.6 D) 4913.5 E) None of the above
12. 1884 + 677 + 3745 ÷ 16 = ?
A) 2795 B) 1334 C) 4335 D) 6781 E) None of the above
13. 88 + 0.88 + 88.98 + 7.8 + 0.0088 = ?
A) 244.66 B) 185.66 C) 311.55 D) 455.66 E) None of the above
Sol: = 88 + 0.88 + 88.98 + 7.8 + 0.0088 = 185.66
Ans: B
15. (9962) ÷ 34 + 160 − 102 = ?
A) 351 B) 442 C) 673 D) 541 E) 667
26. 19(119 ÷ 17) − 149 + 2005 = ?
A) 1989 B) 1991 C) 2005 D) 2001 E) 1967
Some more....
1. What should come in place of ?
65412 + 42548 + 42565 = ?
A) 153547 B)150525
C)154549 D) 156542 E) 155693
Sol: Unit digit of a sum will always depend on
the unit digit of individual numbers.
So, 2 + 8 + 5 = 5 (last digit)
Ans: B
2. What should come in place of ?
2472 ÷ 48 ÷ 5 = ?
A) 10.3 B) 17.4 C) 16.3
D) 15.8 E) 23.1
1 1
Sol:
Ans: A
3. What should come in place of ?
652 − 592 + 392 = ?
A) 2442 B) 2046 C) 2031
D) 2265 E) 2232
Sol: 652 − 592 + 392 = ?
= 4225 − 3481 + 1521 = 2265
Ans: D
4. What should come in place of ?
763 ÷ 14 = ? − 25.5
A) 85 B) 80 C) 40
D) 14 E) 90
Sol: 763 ÷ 14 = ? − 25.5
? = 763 ÷ 14 + 25.5
? = 80
Ans: B
5. What should come in place of ?
(36 × 19 − 324) ÷ 18 = ?
A) 20 B) 26.8 C) 41.8
D) 45 E) 57.5
Sol: (36 × 19 − 324) ÷ 18 = ?
? = (36 × 19 − 324) ÷ 18 = 20
Ans: A
6. What should come in place of ?
A) 53 B) 39 C) 45
D) 43 E) 52
Sol:
Ans: B
7. What should come in place of ?
75% of 960 × 37.5% of 560 = ?
A) 151200 B) 125410 C) 156000
D) 152000 E) 123520
Sol: 75% of 960 × 37.5% of 560 = ?
= 0.75 (960) × 0.375 (560) = 151200
Ans: A
8. What should come in place of ?
35% of 140 + 45% of 160
= 87.5% of 120 + ?
A) 17 B) 16 C) 19.5
D) 17.5 E) 15.6
Sol: 35% of 140 + 45% of 160
= 87.5% of 120 + ?
? = 49 + 72 − 105 = 16
Ans: B
9. What should come in place of ?
140% of 250 + 120% of 320
= 150% of 240 + ?
A) 444 B) 474 C) 347
D) 374 E) 396
Sol: 140% of 250 + 120% of 320
= 150% of 240 + ?
? = 350 + 384 − 360 = 374
? = 374
Ans: D
10. What should come in place of ?
1782 ÷ 36 + 149 = ? − 412
A) 1752.5 B) 1879.5 C) 1732.5
D) 1058.5 E) 1875.5
Sol: 1782 ÷ 36 + 149 = ? − 412
? = 49.5 + 149 + 1681 = 1879.5
Ans: B
11. What should come in place of ?
1874 + 1457 + 2870 ÷ 14 = ?
A) 3498 B) 3536 C) 3758
D) 3960 E) 3675
Sol: 1874 + 1457 + 2870 ÷ 14 = ?
Ans: B
12. What should come in place of ?
76.5 + 7.65 + 0.765 + 765 + 0.0765 + 7650
= ?
A) 8499.4762 B) 8745.245
C) 8445.7575 D) 8499.9915
E) 8749.2895
Sol: 76.5 + 7.65 + 0.765 + 765 + 0.0765 + 7650
= 8499.9915
Ans: D
13. What should come in place of ?
A) 4 B) 6 C) 25 D) 18 E) 10
Sol:
Ans: A
14. What should come in place of ?
(8208) ÷ 36 + 163 − 141 = ?
A) 254 B) 244 C) 250
D) 450 E) 270
Sol: (8208) ÷ 36 + 163 − 141 = ?
? = 228 + 22 = 250
Ans: C
15. What should come in place of ?
A) 625 B) 364 C) 325
D) 225 E) 334
Sol:
Ans: D
16. What should come in place of ?
(50 × ?) + 45 × 36 = 1720
A) 2 B) 4 C) 6 D) 20 E) 5
Sol: (50 × ?) + 45 × 36 = 1720
(50 × ?) = − 45 × 36 + 1720
Ans: A
17. What should come in place of ?
70% of 530 + ? = 45% of 1250 + 50% of 1700
A) 1835.75 B) 1825.5
C) 812.5 D) 1041.5 E) 1826
Sol: 70% of 530 + ?
= 45% of 1250 + 50% of 1700
? = 45% of 1250 + 50% of 1700 − 70% of 530
? = 562.5 + 850 − 371
? = 1041.5
Ans: D
18. What should come in place of ?
A) 720 B) 779 C) 736
D) 756 E) 956
Sol:
Ans: B
19. What should come in place of ? 4266 ÷ 18 + ? × 4 = 80
A) 39.25 B) 24.25 C) 35.55
D) 31.26 E) 34.52
Sol: 4266 ÷ 18 + ? × 4 = 80
? × 4 = 237 − 80
? = 157 ÷ 4 = 39.25
Ans: A
20. What should come in place of ?
A) 420 B) 497 C) 457
D) 452 E) 416
Ans: B
21. What should come in place of ?
A) 130 B) 182 C) 126
D) 112 E) 188
Sol:
Ans: B
* What should come in place of ?
3952 ÷ 26 × 15 + 625 − 343 = ?
A) 2562 B) 2954
C) 2263 D) 2142
E) 4125
Sol: 3952 ÷ 26 × 15 + 625 − 343 = ?
? = 152 × 15 + 282
? = 2562
Ans: A
* What should come in place of ?
24512 + 65245 − 41254 − 45241 = ?
A) 3262 B) 3141
C) 3154 D) 3156
E) 2135
Sol: Unit digit of a sum will always depend on the unit digit of individual numbers.
24512 + 65245 − 41254 − 45241 = ?
So, 2 + 5 − 4 − 1 = 2
Ans: A
* What should come in place of ?
A) 3356 B) 3180
C) 3080 D) 3564 E) 3304
Sol:
Ans: E
* What should come in place of ? (26 × 12 × 17) ÷ (13 × 6) = Ö ¾?
A) 4125 B) 4225
C) 4624 D) 4251
E) 4620
Sol:
Ans: C
* What should come in place of x
45% of 120 + x% of 500
= 60% of 1800
A) 250.35 B) 224.36
C) 225.75 D) 205.2
E) 212.6
Sol: 45% of 120 + x% of 500
= 60% of 1800
5x = 60% of 1800 − 45% of 120
5x = 1026
Ans: D
Directions (Q. 1 - 10): What will come in place of question mark (?) in the following questions?
1. 3463 × 295 − 18611 = ? + 5883
Ans: 997091
Exp:
3463 × 295 − 18611 = ? + 5883
? = 1021585 − 18611 − 5883 = 997091
2. 2652 ÷ 39 ÷ 17 = ?
Ans: 4
Exp:
Ans:
Exp:
4. (4444 ÷ 40) + (645 ÷ 25) + (3991 ÷ 26) = ?
Ans: 290.4
Exp:
(4444 ÷ 40) + (645 ÷ 25) + (3991 ÷ 26)
111.1 + 25.8 + 153.5 = 290.4
Ans: 382
Exp:
Ans: 3721
Exp:
Ans: 64
Exp:
8. (2746 × 49) + 150180 = ? × 118
Ans: 2413
Exp:
Ans: 3
Exp:
10. 362.3 × 61.4 ÷ 60.8 = 36?
Ans: 2.6
Exp:
Directions (Q. 11 - 20): What approximate value should come in place of question mark (?) in the following questions?
Note: You are not expected to calculate the exact value.
11. 39.897% of 4331 + 58.779% of 5003 = ?
Ans: 4700
Exp:
39.897% of 4331 + 58.779% of 5003
= 40% of 4330 + 60% of 5000
= 1732 + 3000 = 4732 ≈ 4700
Ans: 10
Exp:
13. 43931.03 ÷ 2111.02 × 401.04 = ?
Ans: 8300
Exp:
43931.03 ÷ 2111.02 × 401.04
43930 ÷ 2110 × 400
20.8 × 400 = 8320 ≈ 8300
Ans: 180
Exp:
Ans: 4890
Exp:
16. 1339.28% of 49.67 = ?
Ans: 670
Exp:
1339.28% of 49.67
1340% of 50 = 50% of 1340 = 670
17. 335.01 × 244.99 ÷ 55 = ?
Ans: 1490
Exp:
335.01 × 244.99 ÷ 55
= 335 × 245 ÷ 55
= 335 × 4.45 ≈ 1490
Ans: 51
Exp:
19. 124.945 + 7.894 × 1.493 = ?
Ans: 137
Exp:
124.945 + 7.894 × 1.493 = ?
125 + 8 × 1.5 = 137
20. (352 % of 49.6) − 74.638 = ?
Ans: 100
Exp:
(352% of 49.6) − 74.638
350% of 50 − 75 = 100
Directions (Q. 21 - 25): What should come in place of question mark (?) in the following questions?
21. (56 × 280) ÷ (14 × 112) = ?
Ans: 10
Exp:
(56 × 280) ÷ (14 × 112)
22. 9207 ÷ 27 × (0.2)2 = ?
1) 136.4 2) 2492 3) 1.364 4) 126.7 5) None of these
Ans: 5
Exp:
9207 ÷ 27 × (0.2)2
Ans: 3
Exp:
Ans: 616
Exp:
Ans:
Exp:
SIMPLE INTEREST & COMPOUND INTEREST
1. The simple interest on a sum of money is 1/9 of the principal and the number of years is equal to the rate percentage per annum. Find the rate percentage.
a) 3% b) 1/3% c) 10% d) 9%
Sol: Let R be the rate percentage. Then,
Ans: b
2. The difference between the CI and SI on a certain sum of money at 5% per annum for 2 years is Rs.1.50. Find the sum.
a) Rs.6,000 b) Rs.1,200 c) Rs.600 d) Rs.300
Ans: c 3. The simple interest on a certain sum of money at 4% per annum for 4 years is Rs.80 more than the simple interest on the same sum of money for 3 years at 5% per annum. Find the sum.
a) Rs.4,000 b) Rs.8,000 c) Rs.4,030 d) None of these
Sol: Let the principal amount be P. Then, 4
Ans: b
4. In what time will Rs.2,000 amount to Rs.2,500 at 10% per annum simple interest?
a) 2.5 years b) 1.5 years c) 2 years d) 5 years
Sol: Let T be the time. Then,
Ans: a
5. A sum invested at 4% simple interest p.a. grows to Rs.648 in 5 years. In two years the same amount at 10% simple interest p.a. will grow to
a) Rs.600 b) Rs.650 c) Rs.648 d) Rs.594
Sol: Let sum be Rs.x, then SI = Rs.(648 - x)
Ans: c
6. Ravi borrowed Rs.5,000 for 10 years at the rate of 3% per annum SI from Raj. How much interest will Raj earn at the end of this period?
a) Rs.1,500 b) Rs.1,000 c) Rs.15,000 d) Rs.1507
Sol: P = Rs.5,000 r = 3% p.a. n = 10 years
Ans: a
7. If a sum of money at a certain rate of simple interest doubles in 5 years and at a different rate of simple interest becomes three times in 12 years, the better rate of interest is in
a) Case-1 b) Case-2 c) Equal in both cases d) None of these
Sol: Case 1: SI = A - P = 2P - P = P
Hence, rate of interest is better in Case-1.
Ans: a
8. An amount of money becomes Rs.4,840 in 2 years and Rs.5,324 in 3 years on CI. Find the rate percentage per annum.
a) 10% b) 15% c) 12% d) 8%
Ans: a
9. In what time does a sum of money become four times at simple interest rate of 5% per annum?
a) 60 years b) 61 years c) 63 years d) 65 years
Sol: Let the principal amount be p. For it to become four times, interest should be 3p.
Ans: a
10. If a sum on compound interest becomes three times in 4 years, then with the same interest rate, the sum will become 81 times in
a) 16 years b) 8 years c) 12 years d) 24 years
11. Divide Rs.1,105 between A and B, so that the amount of A after 5 years is equal to the amount of B after 7 years, the interest being compounded at 10% per annum.
a) Rs.705, Rs.400 b) Rs.605, Rs.500 c) Rs.650, Rs.455 d) None of these
Sol: Let two parts be Rs.x and
So, the two parts are Rs.605 and (1105 − 605) = Rs.500.
Ans: b
12. Divide Rs.3,650 into two parts such that the SI on the first part at 6% for 2 years is equal to the SI on the second part at 4% in 3 years. Find the two parts.
a) Rs.1,900, Rs.1,750 b) Rs.1,825, Rs.1,825 c) Rs.2,000, Rs.1,650 d) Rs.1,800, Rs.1,850
Sol: First part = Rs.x, R = 6%, N = 2 years
Second part = 3,650 − x, R = 4%, N = 3 Years
According to the given condition,
⇒ 2x = 3650
⇒ x = Rs.1,825
Second part = 3,650 - 1,825 = Rs.1,825.
Ans: b
13. A bank offers 5% per annum CI calculated on half-yearly basis. A customer deposited Rs.1,600 each on January 1 and July 1 of a year. The interest he would have gained at the end of the year is
a) Rs.120 b) Rs.244 c) Rs.121 d) Rs.81
Sol: Since rate of interest is half yearly
Total CI = 3,321 − 1,600 − 1,600 = Rs.121.
Ans: c
14. The rate of interest for the first 2 years is 6% per annum, for the next 3 years is 16% per annum, and for the period beyond 5 years is 20% per annum. If a man gets Rs.6,080 as a simple interest for 6 years, then how much amount did he deposit?
a) Rs.8,000 b) Rs.6,400 c) Rs.7,600 d) Rs.7,200
Sol: Let deposited amount be Rs.x. Then,
⇒ x = Rs.7,600
Ans: c
15. A man borrows Rs.6,720 to be paid back with compound interest at the rate of 10% per annum by the end of 2 years in two equal yearly installments. How much will each installment be?
a) Rs.3,608 b) Rs.3,902 c) Rs.3,872 d) Rs.4,048
Sol: Let the value of each installment be x, Then,
So, each installment = Rs.3,872
Ans: c
16. The CI and SI on a certain sum for 2 years is Rs.40.80 and Rs.40 respectively. Find the rate of interest per annum and the sum.
a) 3%, Rs.425 b) 4%, Rs.500 c) 5%, Rs.600 d) 2%, Rs.620
Ans: b